Solution to PS 1 #6 Use the Henderson - Hassalbalch Equation:
pH = pKa + log [A-]/[HA]
Let x=ratio=[CH3-COO-]/[CH3-COOH]; pH = 5.00; pKa=4.76
5.00 = 4.76 + log(x)
log (x) = 5.0-4.76= 0.24
x = 10 0.24= 1.7
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