Solution to PS 7 #10
The chances of finding an A is 0.5(0.64)= 0.32
The chances of finding a T is 0.5(0.64)=0.32
The chances of finding a G is 0.5(0.36)=0.18
The chances of finding a C is 0.5(0.36)=0.18
The overall chance of finding AAGCTT
in a 100 Mb DNA is 100,000,000/((0.32)(0.32)(0.18)(0.18)(0.32)(0.32))=33,979
times.
Go back to Problem Set 7